What is the required circuit ampacity for a noncontinuous, single-phase load of 8.5kW at 277V?

To determine the required circuit ampacity for a noncontinuous, single-phase load of 8.5 kW at 277V, one must first convert the kilowatts into amperes using the formula:

[ \text{Amperes} = \frac{\text{Watts}}{\text{Volts}} ]

In this case, the load is 8.5 kW, which can be converted to watts:

[ 8.5 , \text{kW} = 8500 , \text{W} ]

Now, substituting the values into the formula provides:

[ \text{Amperes} = \frac{8500 , \text{W}}{277 , \text{V}} ]

Calculating this yields:

[ \text{Amperes} \approx 30.69 , \text{A} ]

For noncontinuous loads, the ampacity calculated is the value needed under normal operating conditions since the load does not exceed 3 hours of continuous operation. Therefore, 30.69A is the correct calculation for the required circuit ampacity of an 8.5 kW load at 277 volts.

The fact that this calculation