What is the load center length for a branch circuit with noncontinuous loads of 125A at 80' from the source, 75A at 110' from the source, and 50A at 100' from the source?

To determine the load center length for a branch circuit with noncontinuous loads, the calculation involves finding the equivalent length of the circuit based on the loads and their distances from the source. Here, you need to weigh the loads against their respective distances.

For each load, you can find its contribution to the total length by multiplying the load (in amperes) by its respective footer distance:

1. For the 125A load at 80': (125 \text{ A} \times 80 \text{ ft} = 10000 \text{ A-ft})

2. For the 75A load at 110': (75 \text{ A} \times 110 \text{ ft} = 8250 \text{ A-ft})

3. For the 50A load at 100': (50 \text{ A} \times 100 \text{ ft} = 5000 \text{ A-ft})

Adding these together gives the total load in A-ft:

[

10000 + 8250 + 5000 = 26250 \text{ A-ft}

]

Next, to find the total amperage (the sum of the loads):

[

125 +